Question

Claculati volumul de acid acetic de concentratie 1 molar, ce reactioneaza cu 500 ml sol. oxid de magneziu de concentratie 2 molar.

Answer 1

Cm=n/Vs(L)==>n=Cm*Vs=2*0.5=1 mol MgO

2mol...................1mol
2CH3-COOH + MgO --> (CH3-COO)2Mg + H2O
x=2mol...............1mol

Cm=n/Vs==>Vs=n/Cm=2/1=2L acid acetic

Answer 2

Imi pare rau dar nu poate exista o solutie de oxid de magneziu deoarece oxidul de magneziu(MgO) reactioneaza cu apa si formeaza hidroxid de magneziu(Mg(OH)2) in cazul in care la acesta te refereai uite rezolvarea:

CmCH3COOH=1M
VsMg(OH)2=500mL=0.5L
CmMg(OH)2=2M

Cm=nd/Vs

nd - nr. de moli de subst. dizolvata

Vs-Volumul solutiei exprimat in litri

2=nd/0.5=>2nd=2=>nd=1

nMg(OH)2=1 mol

Mg(OH)2+2CH3COOH-->(CH3COO)2Mg+2H2O

nMg(OH)2/nCH3COOH=1/2=>nCH3COOH=2nMg(OH)2

nCH3COOH=2×1=2 moli

Cm=nd/Vs

CmCH3COOH=1M
nCH3COOH=2 moli
1=2/Vs=>Vs=2×1=2L