Question

clasa a 8-a!!!acest exercitiu!​

Answer 1

Explicație pas cu pas:

E(x)=(x²+x-1)²-(x²-2)²-2x(x+1)(x-1)+3

Folosim a²-b²=(a+b)(a-b) pentru primii 2 termeni

E(x)=(x²+x-1+x²-2)(x²+x-1-x²+2)-2x(x+1)(x-1)+3 =>

E(x)=(2x²+x-3)(x+1)-2x(x+1)(x-1)+3=>

E(x)=(x+1)*[2x²+x-3-2x(x-1)]+3=>

E(x)=(x+1)(2x²+x-3-2x²+2x)+3=>

E(x)=(x+1)(3x-3)+3=>E(x)=3(x+1)(x-1)+3=>

E(x)=3(x²-1)+3=>E(x)=3x²-3+3=>E(x)=3x²