Question

Clasa a v-a. divizibilitate numere naturale.

Answer 1

 

$\displaystyle\\\text{Calculam paranteza din stanga.}\\\\\Big(\overline{x9x}+\overline{x6}\Big)=\\=100x+90+x+10x+6=\\=\boxed{\Big(111x+96\Big)}\\\\\text{Calculam paranteza din dreapta.}\\\\\Big(\overline{xx9}+\overline{8x}+7\Big)=\\=100x+10x+9+80+x+7=\\=\boxed{\Big(111x+96\Big)}\\\\\text{Rezulta ca cele doua paranteze sunt egale.}\\\\\implies~~~\Big(111x+96\Big) ~\Big|~2\cdot\Big(111x+96\Big)\\\\\text{sau}\\\\2\cdot\Big(111x+96\Big)~\vdots~\Big(111x+96\Big)$