Question

Clasa a zecea.
Clasa a zecea.​

Answer 1

Răspuns:

Explicație pas cu pas:

Conjugatele numerelor

a) 3-5i  => 3+5i

b) -4i => 4i

c) -2-8i => -2+8i

d) -6i-4  => -4 +6i

            __

e) (1-2i)(1+i) = (1-2i)(1-i) = 1-3i+2i² = 1-3i-2 = -1-3i => -1+3i

f) ___

   -2i · (-i-1) = 2i·(-1-i) = -2i-2i² = -2i+2 => 2+2i

g) (√2-i)(√2+i) = 2-i² = 2+1 = 3  => 3

a) (2+i)/(3+5i) + (2-i)/(3-5i) = [(2+i)(3-5i) + (2-i)(3+5i)]/(9-25i²) =

= (6-7i-5i²+6+7i-5i²)/(9+25) = (12-10i²)/34 =

= 24/34 = 12/17