Question

clorura unui metal divalent contine 74.73% clor Care este masa atomica a metalului

Answer 1

M[tex] Cl_{ 2} [/tex] : 2$A_{Cl}$=$\frac{74.73}{100}$*$M_{ MCl_{2} }$ (1)
$M_{ MCl_{2} }$=$A_{M} + 2 A_{ Cl_{2} }$ (2)
$A_{Cl}$=35.5 (3)
(1),(2),(3)---> 2$A_{Cl}$=$\frac{74.73}{100}$* ($A_{M}$+71) <=>
71*$\frac{100}{74.73}$ - 71= $A_{M}$
$A_{M}$=24