Question

Combinari de 6 luate cate 3 - Aranjamente de 4 luate cate 2 + 3

Answer 1

C₆³ = 6! /  3! · ( 6 - 3 )! = 3! · 4 ·5 · 6 / 3! · 1 · 2 · 3 = 4 · 5 = 20

A₄² = 4! / ( 4 - 2 )! = 2! · 3 · 4 / 2! = 3 · 4 = 12

C₆³ - A₄² + 3 = 20 - 12 + 3 = 8 + 3 = 11

⇒ C₆³ - A₄² + 3 = 11

Answer 2

Răspuns:

C(6,3)=20

C₆³=6!/3!×(6-3)!=4×5=20

si

A(4,2)=12

A₄²=4!/(4-2)!=3×4=12

C₆³-A₄²+3=?

am aflat ca

C₆³=20 iar A₄²=12

deci C₆³-A₄²+3=20-12+3=8+3=11