Question

comparati 2×2^2×2^3×...×2^2002 si (8^77)^8671​

Answer 1

Explicație pas cu pas:

$2 \times {2}^{2} \times ... {2}^{2002} = {2}^{1 + 2 + ... + 2002} = {2}^{ \frac{2002 \times 2003}{2} } = {2}^{1001 \times 2003 } = {2}^{2005003}$

$( {8}^{77} )^{8671} = {8}^{667667} = ({ {2}^{3} })^{667667} = {2}^{2003001}$

${2}^{2005003 } > {2}^{2003001}$