Question

comparati nr: d) x=2^288 si y=3^192

Answer 1

Răspuns:

x<y

Explicație pas cu pas:

x=(2^3)^96=8^96

y=(3^2)^96=9^96

Answer 2

$x=2^{288}=\displaystyle \left(2^3\right)^{\frac{288}{3}}=8^{96}$

$y=3^{192}=\left(3^2\right)^{\frac{192}{2}}=9^{96}$

dar $8^{96} < 9^{96}$

$\implies \boxed{x < y}$