Question

comparati nr reale

3 si 2√2
3√5 si 2√11
cum se rezolva?dupa ce metoda?teorema?
multumesc

Answer 1

$3 \: si \: 2 \sqrt{2} \\ 3 {}^{2} = 9 \\( 2 \sqrt{2} ) {}^{2} = 8 \: \\ = > 3> 2 \sqrt{2} \\ \\ 3 \sqrt{5} \: si \: 2 \sqrt{11} \\( 3 \sqrt{5} ) {}^{2} = 45 \\ (2 \sqrt{11} ) {}^{2} = 44 \\ = > \: 3 \sqrt{5} > 2 \sqrt{11}$