Question

Comparati numarul A=(3^2)^4:3^6*3^2 cu numarul B=8*10^2+0*10+1*10^0

Answer 1

$A = {( {3}^{2}) }^{4} \div {3}^{6} \times {3}^{2}$

$A = {3}^{2 \times 4} \div {3}^{6} \times {3}^{2}$

$A = {3}^{8} \div {3}^{6} \times {3}^{2}$

$A = {3}^{8 - 6 + 2}$

$A = {3}^{4}$

$A = 81$

$B = 8 \times {10}^{2} + 0 \times 10 + 1 \times {10}^{0}$

$B = 8 \times 100 + 0 + 1 \times 1$

$B = 800 + 1$

$B = 801$

$81 < 801 = > A < B$