Question

Comparați numerele :

Answer 1

$3^{20}$* $3^{5 * 4}$=$3^{20}$ * $3^{20}$=$3^{40}$

$9^{21}$=$3^{2*21}$=$3^{42}$

$3^{40}$< $3^{42}$

Answer 2

3^{20}•(3^{5})^{4}=3^{20}•3^{5•4}=3^{20}•3^{20}=3^{20+20}=3^{40}

9^{21}=(3^{2})^{21}=3^{2•21}=3^{42}

3^{40}<3^{42} => x<y