Question

Comparati numerele: 

A=8 la puterea 19 cu B=4 la puterea 28+11*4 la puterea 28-10*4 la puterea 28

Answer 1

$A=8^{19}=(2 ^{3} ) ^{19} =2 ^{3*19} =2 ^{57}$

$B=4 ^{28} +11*4^{28} -10*4 ^{28}=4 ^{28}(1+11-10)= 4^{28} *2=$$( 2^{2} ) ^{28} *2= 2^{2*28+2} =2 ^{56+2} =2 ^{58}$

$2^{57} <2 ^{58}$
A<B