Question

Comparati numerele a si b ,unde a=[(2^3)^5 + 25^3-7^35:7^20]:(2^15-7^15+5^6)*3^26 si b=2^101:[(5^171:5^170-3)^98+2105:(2^*2^4)+(2^11)^9]*2^38
Va rog frumos ajutatima!!

Answer 1

a=[(2^3)^5 + 25^3-7^35:7^20]:(2^15-7^15+5^6)*3^26 =
=[(2^15 + 5^6-7^15]:(2^15-7^15+5^6)*3^26 =
=1*3^26=3^26 
a=3^26=(3^2)^13=9^13

b=2^101:[(5^171:5^170-3)^98+2^105:(2^3*2^4)+(2^11)^9]*2^38=
=2^101:[(5-3)^98+2^105:2^7+2^99]*2^38=
=2^101:[2^98+2^98+2^99]*2^38=
=2^101:[2^98(1+1+2)]*2^38=
=2^101:(2^98*2^2)*2^38=
=2^101:2^100*2^38=
=2*2^38=
=2^39
b=2^39=(2^3)^13=8^13

rezulta a>b