Question

Comparati numerele: A=$\frac{1}{2}$+$\frac{1}{6} }$: $\frac{1}{3} }$ si b=[0,3+0,(3)]:0,6(3).

Answer 1

a=1/2+1/6·3/1
a=1/2+1/2
a=2/2⇒a=1valoare numarului;
b=[3/10+3/9]/63-6/90
b=[3/10+3/9]/57/90
b=[3/10+3/9]/19/30
b=[3/10+3/9]·30/19
b=[27/90+30/90]·30/19
b=57/90·30/19
b=19/30·30/19⇒b=1/1⇒b=1⇒valoarea numarului;
⇒1=1⇒a=b;