Question

comparati numerele x si y in fiecare caz x=(27^31-2 * 9^46+4^102:2^203-3^92)^213 cu y =(-3)^142

Answer 1

x = (27^31-2×9^46+4^102:2^203-3^92)^213

x = [(3^3)^31-2×(3^2)^46+(2^2)^102:2^203-3^92]^213

x = (3^93-2×3^92+2^204:2^203-3^92)^213

x = (3^93-2×3^92+2^1-3^92)^213

x = [3^92 × ( 3 - 2 - 1) + 2 ]^213

x = (3^92 × 0 + 2)^213

x = (0 + 2)^213

x = 2^213
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y = ( - 3)^142 = 3^142; ( - ) la o putere para se va transforma in ( + )

x = 2^213 = (2^3)^71 = 8^71

y = 3^142 = (3^2)^71 = 9^71

8^71 < 9^71 => 2^213 < ( -3)^142 => x < y
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