Question

Completaţi astfel incat sa obţineti o egalitate adevarata​

Answer 1

Punctul A

$\displaystyle{ -3\frac{1}{3} - x = 2}$

$\displaystyle{ - \frac{10}{3} - x = 2 }$

$\displaystyle{ x = -\frac{10}{3} - 2 }$

$\displaystyle{ x = -\frac{10}{3} - \frac{6}{3} }$

$\displaystyle{ x = -\frac{16}{3} }$

Punctul B

$\displaystyle{ x + (-4,5) = 3\frac{1}{2} }$

$\displaystyle{ x - 4,5 = \frac{7}{2} }$

$\displaystyle{ x - 4,5 = 3,5 }$

$\displaystyle{ x = 3,5 + 4,5}$

$\displaystyle{ x = 8 }$

Punctul C

$\displaystyle{ x \cdot (-\frac{7}{8}) = 5,6 }$

$\displaystyle{ \frac{-7x}{8} = \frac{56}{10} }$

$\displaystyle{ -7x \cdot 10 = 8 \cdot 56 }$

$\displaystyle{ -70x =448 }$

$\displaystyle{ x = 448 : (-70) }$

$\displaystyle{ x = -6,4 }$

Punctul D

$\displaystyle{ (-10\frac{ 1}{5}) : x = 2 }$

$\displaystyle{ (-\frac{51}{5}) : x = 2 }$

$\displaystyle{ x = (-\frac{51}{5}) : 2 }$

$\displaystyle{ x = (-\frac{51}{5}) \cdot \frac{1}{2} }$

$\displaystyle{ x = -\frac{51}{10} }$

$\displaystyle{ x = -5,1 }$

Punctul E

$\displaystyle{ x : 4,5 = \frac{1}{3} }$

$\displaystyle{ x : \frac{45}{10} = \frac{1}{3} }$

$\displaystyle{ x = \frac{1}{3} \cdot \frac{45}{10} }$

$\displaystyle{ x = \frac{45}{30} }$

$\displaystyle{ x = \frac{3}{2} }$

$\displaystyle{ x = 1,5 }$

Punctul F

$\displaystyle{ x : 10^{2}= -0,02 }$

$\displaystyle{ x = -0,02 \cdot 10^{2} }$

$\displaystyle{ x = -0,02 \cdot 100 }$

$\displaystyle{ x = -2}$

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Answer 2

$\bf a)\,-3\dfrac{1}{3} -x=2 \implies x=-3\dfrac{1}{3} -2$

$\bf x=-\dfrac{3\cdot 3+1}{3} -2=-\dfrac{10}{3} - 2$

$\bf x=-\dfrac{10}{3} -\dfrac{6}{3} = \boxed{\bf -\dfrac{16}{3} }$

$\bf b)\, x+(-4,5)=3\dfrac{1}{2} \implies x-4,5=\dfrac{3 \cdot 2+1}{2}$

$\bf x-4,5=\dfrac{7}{2} \implies x-4,5=3,5$

$\bf x=3,5 + 4,5 \implies \boxed{\bf x=8}$

$\bf c)\, x \cdot \bigg(-\dfrac{7}{8} \bigg)=5,6 \implies -\dfrac{7}{8} x=5,6 \; | \cdot \bigg(-\dfrac{8}{7} \bigg)$

$\bf x=-\dfrac{8}{7} \cdot 5,6 \implies x= -\dfrac{8}{7} \cdot \dfrac{56}{10} ^{(2}$

$\bf x=-\dfrac{8 \cdot 28 }{7 \cdot 5} ^{(7}=-\dfrac{8\cdot 4}{5} \implies \boxed{\bf x=-\dfrac{32}{5} }$

$\bf d)\, \bigg(-10\dfrac{1}{5} \bigg) : x=2 \implies -\dfrac{10\cdot 5+1}{5} :x=2$

$\bf -\dfrac{51}{5} :x =2 \implies -\dfrac{51}{5} \cdot \dfrac{1}{x} =2$

$\bf -\dfrac{51}{5x} =2 \; |\cdot 5x \implies -51=10x \implies \boxed{\bf x=-\frac{51}{10} }$

$\bf e)\, x:4,5=\dfrac{1}{3} \implies x:\dfrac{45}{10}^{(5} =\dfrac{1}{3} \implies x:\dfrac{9}{2} =\dfrac{1}{3}$

$\bf x \cdot \dfrac{2}{9} =\dfrac{1}{3} \implies x=\dfrac{1}{3} :\dfrac{2}{9} =\dfrac{1}{3} \cdot \dfrac{9}{2} \implies \boxed{\bf x=\dfrac{3}{2} }$

$\bf f)\, x:10^2=-0,02 \implies \dfrac{x}{10^2} =-0,02$

$\bf \dfrac{x}{100} =-0,02 \implies x= -0,02 \cdot 100 \implies \boxed{\bf x=-2}$

Bafta! :)

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