Question

Completati tabelul cu: ii) elementele unui pătrat, dimensiunile fiind exprimate in centimetri​

Answer 1

a)

P=4*l=$24\sqrt{3}$=> l=6$\sqrt{3}$

R=$\frac{l\sqrt{2} }{2} =\frac{6\sqrt{6} }{2} =3\sqrt{3}$

a=$\frac{l}{2} =3\sqrt{3}$

A=l$^{2} =36*3=108$

b)

A=$l^{2} =128=>l=8\sqrt{2}$

R=$\frac{l\sqrt{2} }{2} =8$

a=l/2=$4\sqrt{2}$

P=4*$8\sqrt{2} =32\sqrt{2}$

c)

a=l/2=$4\sqrt{3}=>l=8\sqrt{3}$

R=$\frac{l\sqrt{2} }{2} =4\sqrt{6}$

A=$l^{2} =64*3=192$

P=$4*8\sqrt{3} =32\sqrt{3}$

d)

l=$\sqrt{72} =6\sqrt{2}$

R=$\frac{l\sqrt{2} }{2} =6$

a=$\frac{l}{2} =3\sqrt{2}$

A=$l^{2} =72$

P=4*l=$24\sqrt{2}$

e)

R=$\frac{l\sqrt{2} }{2} =4\sqrt{6}=>l\sqrt{2}=8\sqrt{6}=>l=\frac{8\sqrt{6}}{\sqrt{2}} =8\sqrt{3}$

a=l/2=$4\sqrt{3}$

A=$l^{2} =64*3=192$

P=4*l=$32\sqrt{3}$

Bafta!