Question

Completati tabelul :
e un tabel cu cateva coloane , in care se da pe fiecare coloana
a=2; 3√5 ; √3 ; 1 supra √5; √7; √3- √2; 3+√5
b= 8; √5; √27; 1 supra √125; √7; √3+√2
si se cere ma = a+b supra2
mg= √a•b
cum am scris numerele is unele sun altele si asa se calculeaza .

Answer 1

a=2; 3√5 ; √3 ; 1 supra √5; √7; √3- √2; 3+√5
b= 8; √5; √27; 1 supra √125; √7; √3+√2  3-√5
si se cere ma = a+b supra2
mg= √a•b
(2+8)/2=5
√(2x8)=4

(3√5+√5)/2=2√5
√(3√5x√5)=√15

(√3+√27)/2=(√3+3√3)/2=2√3
√(√3x√27)=√81=9

(1/√5+1/√125)/2=(1/√5+1/5√5)/2=[(√5+1)/5√5]/2=(√5+1)/10√5=
(5+√5)/50
√(1/√5x1/√125)=√(1/√625)=√1/25=1/5

(√7+√7)/2=√7
√(√7x√7=√7

(√3-√2+√3+√2)/2=√3
√(√3-√2)(√3+√2)=√(3-2)=1

(3+√5+ 3-√5 )/2=3
√(3+√5)(3-√5)=√(9-5)=√4=2