Question

Compozitia procentuala :CaCO3 , va rog ! Dau coronita ❤️

Answer 1

Comp. proc . prin masa molara

M CaCO3=40 + 12  + 3.16

               =100------> 100g/moli

100 g CaCO3-----------40 g Ca ---------12 g C---------48 g O

100g------------------------x--------------------y--------------------z

x=40% Ca

y=12 % C

z=48% O