Question

Continutul in carbon al unui amestec echimolecular de etilbenzen si naftalina .

Answer 1

1 mol C6H5-CH2-CH3      1 mol C8H10=106g
1 mol C10H8                     1 mol C10H8=128g

masa amestec= 106+128=234g
masa carbon= 12(8+10)=216g

234g amestec hidrocarbura...........216g
100g amestec hidrocarbura............x
x= 92,3%