Question

coroana!
Calculati (c.m.m.d.c) al urmatoarelor perechi de numere
(270, 405, 162)
(2604, 4488)
(578 ,490 ,976, 2254)
[36, 64 ,76]
[144 196 ,96]
[6327 ,25308]

Answer 1

270=2x5x$3^{3}$
405=5x$3^{4}$
162=2x$3^{4}$
(270,405,162)=$3^{3}$
                      =27
2604=$2^{2}$x3x7x31
4488=$2^{3}$x3x11x17
(2604,4488)=$2^{2}$x3
                   =4x3
                   =12
578=2x$17^{2}$
490=2x5x$7^{2}$
976=$2^{3}$x47
2254=2x23x$7^{2}$
(578,490,976,2254)=2

 36=$2^{2}$x$3^{2}$
64=$2^{6}$
76=$2^{2}$x19
(36,64,76)=$2^{2}$
                =4
144=$2^{4}$x$3^{2}$
196=$2^{2}$x$7^{2}$
96=$2^{5}$x3
(144,196,96)=$2^{2}$
                    =4
6327=$3^{2}$x19x37
25308=$2^{2}$x$3^{2}$x19x37
(6327,25308)=$3^{2}$x19x37
                     =9x19x37
                     =171x37
                     =6327
Sper ca te-am ajutat.Daca mai ai altceva,spune-mi!