Question

COROANA! Determanti cel mai mic numar natural care, impartit pe rand la 25 20 si 12 da resturile 24 19 si 11

Answer 1

n=25a+24
n=20b+19
n=12c+11

n+1=25a+24+1=25a+25= 25(a+1)
n+1=20b+19+1=...............= 20(b+1)
n+1=12c+11+1=................=12(c+1)

25|n+1
20|n+1
12|n+1

(n+1) minim= c.m.m.m.c (12,20,25)=3*2²*5²=384*25=300
n mimin=n+1-1=300-1=299, cerinta