Question

Coroana va rog! exericiul 4

Answer 1

a=($2\sqrt{2} + \sqrt{2} ) (3 \sqrt{3}- \sqrt{3} ) = 9 \sqrt{6} -3 \sqrt{6} =3 \sqrt{6}$

b=$\sqrt{2}(2 \sqrt{3} +10 \sqrt{3}):( \sqrt{2}+4 \sqrt{2}-3 \sqrt{3})= \frac{12 \sqrt{6} }{2 \sqrt{2} }$

a$\sqrt{2}=3 \sqrt{12}$

(a$\sqrt{2} ):b=3 \sqrt{12} * \frac{2 \sqrt{2} }{12 \sqrt{6} }= \frac{2 \sqrt{6} }{2 \sqrt{6} } =1$