Question

Coroana!!
x^2=(√2-5)^2 care sunt valorile reale ale lui x1 si x2?

Answer 1

x²=(√2–5)²
|x|=√2–5 <=> x1=√2–5 V x2=–(√2–5)=5–√2
S={√2–5; 5–√2}

Answer 2

 
[tex]\it x^2=(\sqrt2-5)^2 \Leftrightarrow x^2=(5-\sqrt2)^2 \Leftrightarrow \sqrt{x^2} = \sqrt{(5-\sqrt2)^2 } \Leftrightarrow \\ \\ \Leftrightarrow |x| = |5-\sqrt2| \Leftrightarrow |x| = 5-\sqrt2 \Leftrightarrow x = \pm(5-\sqrt2) \\ \\ x _1 = -5+\sqrt2 \\ \\ x_2= 5-\sqrt2 [/tex]