Question

Coroanaaaaaa exercitiul 5

Answer 1

x=$( \sqrt{3}+ \sqrt{2}+1) ^{2} -2( \sqrt{6} + \sqrt{3} - \sqrt{2} )-4 \sqrt{2}=$$3+2+1+2 \sqrt{3} \sqrt{2}+2 \sqrt{2}+2 \sqrt{3} -2 \sqrt{3} \sqrt{2} -2 \sqrt{3} +2 \sqrt{2} -4 \sqrt{2}=6$