Question

cu cate grame de clor reactioneaza 10 grame Mg(magneziu) de puritate 96%. Cati moli de MgCl2(clorura de magneziu) se obtin?
VA ROG AJUTATI-MA!!!!!!!!!!
REPEDEEEEE!!!!
DAU COROANA!

Answer 1

Mg+Cl2=MgCl2

$M_{Mg}=24$

$M_{Cl2}=2*35,5=71$

$M_{MgCl2}=24+71=95$

Calculam masa pura de Mg:

$m= \dfrac{96*10}{100}=9,6 \ g \ Mg$

Aplicam regula de 3 simpla:

24 g Mg.........71 g Cl2......95 g MgCl2
9,6 g Mg.............x................y

$x= \dfrac{9,6*71}{24}=28,4\ g \ Cl2$

$y= \dfrac{9,6*95}{24}=38\ g\ MgCl2$

Transformam masa de MgCl2 in moli:

$n= \dfrac{38}{95} =0,4 \ moli \ MgCl2$

Sper ca te-am ajutat :)