Question

Cu cati moli de CH3I se pot alchila la maxim monoaminele naftalinei?

Answer 1

C10H7-NH2 = naftilamina

C10H7-NH2 + I-CH3 => C10H7-NH-CH3 + HI

metil-naftil-amina

C10H7-NH-CH3 + I-CH3 => C10H7-N-(CH3)2 + HI

dimetil-naftil-amina

C10H7-N-(CH3)2 + I-CH3 => C10H7-$N^{+}$-(CH3)3 + HI

C10H7-$N^{+}$-(CH3)3 = trimetil-naftil-amoniu

=> 3 moli maxim