Question

Cu rezolvari complete :

Answer 1

a)(x+2)(2x-3)=x²-3x+4x-6=x²+x-6
b) E(x)=[2/(x+5)-(x-6)/(x-5)(x+5)+x/-(x-5)]:(x+2)(2x-3)/-(x²-25)
E(x)=[2(x-5)-(x-6)-x(x+5)]/[(x-5)(x+5)]·(-1)(x+5)(x-5)/(x+2)(2x-3)=simplif.cu (x+5)(x-5)=
E(x)=[-(2x-10-x+6-x²-5x)]/[(x+2)(2x-3)=
E(x)=(x²+4x+4)/(x+2)(2x-3)
E(x)=(x+2)(x+2)/(x+2)(2x-3)=simplif cu x+2
E(x)=(x+2)/(2x-3)

c) E(a)=(a+2)/(2a-3)
cond 2a-3≠0⇒a≠3/2
a+2=0
a=-2