Question

Cum calculeaZa 3aupra10+2supra5; 1supra6+2supra3;3supra5+1supra20

Answer 1

Explicație pas cu pas:

$a) \frac{3}{10} + \frac{2}{5} = \frac{3}{10} + \frac{2 \times 2}{5 \times 2} = \frac{3}{10} + \frac{4}{10} = \frac{3 + 4}{10} = \frac{7}{10}$

$b) \frac{1}{6} + \frac{2}{3} = \frac{1}{6} + \frac{2 \times 2}{3 \times 2} = \frac{1}{6} + \frac{4}{6} = \frac{1 + 4}{6} = \frac{5}{6}$

$c) \frac{3}{5} + \frac{1}{20} = \frac{3 \times 4}{5 \times 4} + \frac{1}{20} = \frac{12}{20} + \frac{1}{20} = \frac{12 + 1}{20} = \frac{13}{20}$

Answer 2

Răspuns:

$a) \frac{ {}^{1)} 3}{ \: \: 10 } + \frac{ {}^{2)} 2}{ \: \: 5} = \frac{3 + 4}{10} = \frac{7}{10} \\ numitorul \: comun \: e \: 10$

$b) \: \frac{ {}^{1)} 1}{ \: \: 6} + \frac{ {}^{2)} 2}{ \: \: 3} = \frac{1 + 4}{6} = \frac{5}{6} \\ numitorul \: comun \: e \: 6$

$c) \: \frac{ {}^{4)} 3}{ \: \: 5} + \frac{ {}^{1)} 1}{ \: \: 20} = \frac{12 + 1}{20} = \frac{13}{20} \\ numitorul \: comun \: e \: 20$