Question

Cum dau factor comun m*g in m*g*h-μ*m*g*h supra sin 30 ?

Answer 1

$\frac{m\cdot g \cdot h-u\cdot m \cdot g \cdot h }{sin 30}= \frac{m\cdot g(h-u\cdot h)}{ \frac{1}{2} }= m\cdot g(h-u\cdot h) \cdot \frac{1}{2}$

Am si simplifificat ce se putea.