Question

cum gasesc pe x?

(245:5+5*x):9+89=100

Answer 1

$(245:5+5*x):9+89=100[tex] [tex](49+5*x):9=100-89$
$(49+5*x):9=11$
$49+5*x=11*9$
$49+5*x=99$
$5*x=99-49$
$5*x=50$
$x=50:5$
$x=10$