Question

cum impart numarul 162 in parti direct proportionale cu 2;3 si 5

Answer 1

x + y + z = 162

x / 2 = y / 3 = z / 5 = k

x / 2 = k => x = 2 k

y / 3 = k => y = 3 k

z / 5 = k => z = 5 k

2 k + 3 k + 5 k = 162

10 k = 162

k = 162 / 10

k = 16, 2

x = 2 × 16, 2 = 32, 4

y = 3 × 16, 2 = 48, 6

z = 5 × 16, 2 = 81