Question

cum impart numarul 58 in parti invers proportionale cu 1 cu 3 si cu 5 ?

Answer 1

a+b+c =58
a/1 = b / (1/3) = c / (1/5) = k
⇒ a=k
     b=k/3
     c=k/5
k + k/3 + k/5 = 58
(15k + 5k +3k) / 15 = 58
23 k / 15 = 58 ⇒ k=870/23

a=k=870/23
b=k/3 = 290/23
c=k/5 = 174/23
proba :
870/23 +290/23 +174/23 =1334/23 = 58