Question

Cum pot descompune in produs de doi factori : $2 x^{2}$ +x -6

Answer 1

[tex]2x^2+x-6=0 a=2 b=1 c=-6 delta=b^2-4ac = 1^2-4*2*(-6)=1+48=49 [/tex]

[tex]x1= \frac{-1+7}{4}= \frac{6}{4}= \frac{3}{2} [/tex]

$x2= \frac{-1-7}{4}= \frac{-8}{4}=-2$

Conform formulei $a(x-x1)(x-x2)$

$2(x- \frac{3}{2})(x+2)$

Answer 2

[tex]2x^2+x-6=2x^2+4x-3x-6=2x(x+2)-3(x+2)\\\;\\ =(x+2)(2x-3)[/tex]