Question

Cum pot rezolva in R ecuatia: 4x^2+4x+1=0 ;)

Answer 1

$4x^{2} +4x+1=0 <=> (2x+1)^{2} =0 =>2x+1=0 \\ 2x+1=0=>2x=-1=>x= -\frac{1}{2}$.

Answer 2

4x²+4x+1=0
a=4
b=4
c=1
Δ=b²-4ac
Δ=4²-4·4·1=16-16=0
x₁=(-b+√Δ)/2a
x₂=(-b-√Δ)/2a
x₁=(-4+0)/2·4=-4/8=-1/2
x₂=-4/8=-1/2
S={-1/2}