Question

cum rezolv asta cu cazul 0/0

Answer 1

Salut,

Folosim formula de calcul prescurtat:

(a² -- b²) = (a -- b)(a + b).

$\lim\limits_{x\to -3}\dfrac{x+3}{4x^2-36}=\lim\limits_{x\to -3}\dfrac{x+3}{4(x^2-9)}=\lim\limits_{x\to -3}\dfrac{x+3}{4(x-3)(x+3)}=\\\\\\=\lim\limits_{x\to -3}\dfrac{1}{4(x-3)}=\dfrac{1}{4\cdot(-6)}=-\dfrac{1}{24}.$

Ai înțeles rezolvarea ?

Green eyes.