Question

cum rezolv in numere rationale ecuatia aceasta?

Answer 1

(2x-3)/5=(x-1)/3
Facem produsul pe diagonale si obtinem:
3(2x-3)=5(x-1)
6x-9=5x-5
6x-5x=-5+9
x=4

Verificare:
(2*4-3)/5=(4-1)/3
5/5=3/3
1=1
Solutia este buna.

Answer 2

[tex] \frac{2x-3}{5} = \frac{x-1}{3} =\ \textgreater \ (2x-3)3=(x-1)5 =\ \textgreater \ 6x-9=5x-5 =\ \textgreater \ 6x-5x=-5+9 =\ \textgreater \ x=4[/tex]