Question

Cum rezolv : lim x -> 3 din x la 2 - 1 / x la 2 - 6x - 9?

Answer 1

$\lim_{x \to 3} \frac{x^2-1}{x^2-6x-9} =\frac{3^2-1}{3^2-6*3-9} = \frac{8}{-18} =- \frac{4}{9}$

Answer 2

$\displaystyle \lim_{x \to 3} \frac{x^2-1}{x^2-6x-9} = \frac{3^2-1}{3^2-6 \cdot 3-9} = \frac{9-1}{9-18-9} = \frac{8}{-9-9} =- \frac{8}{18} ^{(2} =- \frac{4}{9}$