Question

Cum rezolvi punctul 4?

Answer 1

poti calcula folosind teorema lui L'Hopital
$\lim_{x \to 1} \frac{ln(2x-1)}{ x^{2}-x-2 } = \lim_{x \to 1} \frac{ \frac{2}{2x-1} }{2x-1}=2$

Answer 2

lim x⇒1 ln(2x-1)/x²+x-2⇒l
limx=⇒ 1⇒ln(2×1-1)/1²+1-2⇒
lim x⇒1⇒ln1/2-2⇒0/0⇒0
sucees