Question

Cum sa rationalizezi numitorii in factori cand ai de exemplu: 2√6 supra 4√3-3√2 ?

Answer 1

$4 \sqrt{3} +3 \sqrt{2} /\frac{2 \sqrt{6} }{4 \sqrt{3}-3 \sqrt{2} }= \frac{2 \sqrt{6}(4 \sqrt{3}+3 \sqrt{2} ) }{(4 \sqrt{3}-3 \sqrt{2})(4 \sqrt{3}+3 \sqrt{2}) } = \frac{8 \sqrt{18}+6 \sqrt{12} }{48-18}= \frac{24 \sqrt{2}+12 \sqrt{3} }{30}$