Question

cum saaflu lui n din egalitatiile 5×n+245=847, 54:n+67×5=344,n:3×8=616,894-n:4=833 repede vaaaaaaa rooooooogggggggggg

Answer 1

5xn+245=847
5xn=847-245
5xn=602
n=602:5
n=120,4
........................................
54:n+67x5=344
54:n+335=344
54:n=344-335
54:n=9
n=54:9
n=6
..........................
n:3x8=616
n:3=616:8
n:3=77
n=77x3
n=231
......................................
894-n:4=833
n:4=894-833
n:4=61
n=61x4
n=244

Answer 2

5×n+245=847
5×n = 847 - 245
5×n = 602
n = 602 : 5
n = 120,4

54:n+67×5=344
54:n + 335 = 344
54:n = 344 - 335
54:n = 9
n = 9×54
n = 486

n:3×8=616
n:3 = 616 : 8
n:3 = 77
n = 77×3
n = 231

894-n:4=833
-n:4 = 833 - 894
-n:4 = -61
-n = -61×4
-n = -244 |×(-1)
n = 244