Question

cum scot factorii de sub radicali la nr √72 si √108


va rog ajutați ma

Answer 1

Rezultat: 72 = 6√2

72 2 } 2

36 2

18 2

9 3 } 3

3 3

1  

Rezultat: 108 = 6√3

108 2 } 2

54 2

27 3 } 3

9 3

3 3

1  

Answer 2

$a)\sqrt{72} = \sqrt{2 \times 2 \times 2 \times 3 \times 3} = \sqrt{(2 \times 2) \times (3 \times 3) \times 2} = \sqrt{ {2}^{2} \times {3}^{2} \times 2 } = (2 \times 3) \sqrt{2} = 6 \sqrt{2}$

$b) \sqrt{108} = \sqrt{2 \times 2 \times 3 \times 3 \times 3} = \sqrt{(2 \times 2) \times (3 \times 3) \times 3} = \sqrt{ {2}^{2} \times {3}^{2} \times 3 } = (2 \times 3) \sqrt{3} = 6 \sqrt{3}$