Question

Cum se afla numerele in perioada??
de exemplu 1,(3) 2,3(4) , 5,(42) , 7,2(42)

Answer 1

1,(3)=1 intreg 3/9 = 12/9

2,3(4)=2 intregi (34-3)/90 = 2 intregi 31/90=(2×90+31)/90=211/90

5,(42)=5 intregi 42/99=(5×99+42)/99=537/99

7,2(42)=7 intregi (242-2)/990=7 intregi 240/990=(7×990+240)/990=7170/990

Answer 2

Daca ai un numar de forma  a,b(c) inseamna ca a iese in fata fractiei ca intreg, numitorul va fi 90,pentru ca avem o zecimala in perioada si una in afar perioadei.Numaratorul va fi numarul bc - b .

1,(3) :
$\\ 1,(3) =1 \frac{3}{9} = \frac{1*9+3}{9} = \frac{12}{9}= \frac{4}{3}$

2,3(4) :
$\\ 2,3(4) = 2 \frac{34-3}{90}=2 \frac{31}{90}= \frac{2*90+31}{90}= \frac{211}{9}$

 5,(42) :
$5,(42) = 5 \frac{42}{99} = \frac{99*5+42}{99}= \frac{537}{99} = \frac{179}{33}$

 7,2(42) :
$7,2(42) =7 \frac{242-2}{990} = \frac{7*990+240}{990}= \frac{7170}{990} = \frac{239}{33}$