Question

Cum se calculeaza :8 la potere 16(2×2 la putere 4 x2 puterea 10 )la puterea 3-2 la puterea 1- 2 la puterea 0

Answer 1

   
[tex]8^{16} : \Big(2 \times 2^4 \times 2^{10}\Big)^3 - 2^1- 2^0= \\ \\ =8^{16} :\Big(2^{1+4+10}\Big)^3 - 2^1- 2^0= \\ \\ =\Big(2^3\Big)^{16} : \Big(2^{15}\Big)^3 - 2^1- 2^0= \\ \\ =2^{3 \times16}:2^{15\times 3} - 2^1- 2^0= \\ \\ =2^{48}: 2^{45} - 2^1- 2^0= \\ \\ =2^{48-45} - 2^1- 2^0= \\ \\ =2^3 - 2^1- 2^0= 8 - 2 - 1 =6 - 1 = \boxed{5}[/tex]