Question

Cum se calculeaza cantitatea de oxigen din
280g CaO
168g KOH
392G H2 SO4
2400gFe2 (SO4)3

Answer 1

1. m = 280
mo=?
M = 40+16
= 56 g
56g CaO. ... 16 gO
280g CaO ... x
x = 280•16/ 56
= 80 g O


2. m=168 g
mO =?
M= 39+16+1
= 56 g
56gKOH ... 16g O
168g KOH ... x
x= 168•16/56
=48gO



3. m=392g
m O=?
M= 2+32+4•16
= 34+64
= 98 g
98gH2SO4 ... 64g O
392gH2SO4 .. x
x= 392•64/98
= 256gO





4 . m=2400g
mO = ?
M= 2•56+3•32+12•16
= 112+ 96+192
= 300 g
300gFe2(SO4)3 .... 192g O
2400Fe2(SO4)3 ... x
x = 2400•192/300
= 1536g O