Question

Cum se calculează la acest exercițiu?Trebuie să îl aflu pe x

Answer 1

2(x+rad3) - rad75 =rad3(2x+1)+4

2x + 2rad3 - 5rad3 = 2x*rad3+rad3 + 4

2x - 2xrad3 = 5rad3 - 2rad3 +rad3 + 4

2x(1-rad3) = 4(rad3+1)

x(1-rad3) = 2(rad3 + 1)

x = 2(rad3+1)/(1-rad3)

x = 2(rad3+1)(1+rad3)/(1-3)

x = 2(rad3+3+1+rad3)/-2

x = -2rad3-4

Answer 2

$\it 2(x+\sqrt3) -\sqrt{75} =\sqrt3(2x+1)+4 \Rightarrow 2x+2\sqrt3-\sqrt{25\cdot3}=\\ \\ =2\sqrt3 x+\sqrt3+4 \Rightarrow 2x-2\sqrt3 x =\sqrt3+4-2\sqrt3+5\sqrt3 \Rightarrow \\ \\ \Rightarrow 2x(1-\sqrt3) =4+4\sqrt3\Rightarrow 2x(1-\sqrt3) =4(1+\sqrt3)|_{:2} \Rightarrow$

$\it\Rightarrow x(1-\sqrt3) =2(1+\sqrt3)|_{\cdot(1+\sqrt3)}\Rightarrow x\cdot(-2)=2(4+2\sqrt3)|_{:(-2)}\Rightarrow\\ \\\Rightarrow x=-(4+2\sqrt3)\Rightarrow x=-4-2\sqrt3$