Question

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Answer 1

pag. 68. Chenar 1:


a) MSO₂ = 64g/mol
raport de masa ⇒ S:O = 32:32 = 1:1

b) MMgO = 40g/mol
raport de masa ⇒ Mg:O = 24:16 = 3:2

c) MP₂O₅ = 142g/mol

raport de masa ⇒ P:O = 62:80 = 31:40

d) MH₂SO₄ = 98g/mol

raport de masa ⇒ H:S:O = 2:32:64 = 1:16:32


pag. 68. Chenar 2:

a) MSO₂ = AS + 2AO = 32+2×16 = 64g/mol

raport de masa ⇒ S:O = 32:32 = 1:1

2 parti masice........1 p.m S............2 p.m O
100 p.m................x........................y

x = 100/2 = 50% S
y = 50% O

b) MH₃PO₄ = 3AH + AP + 4AO = 3×1+31+4×16 = 98g/mol

raport de masa ⇒ H:P:O = 3:31:64 

98 p.m.........3 p.m H........31 p.m P........64 p.m O
100g............x....................y....................z

x = 3×100/98 = 3,061 % H
y = 31/98×100 = 31,63 % P
z = 64/98×100 = 65,3 % O

c) MMg(OH)₂ = AMg + 2(AO+AH) = 24+2(16+1) = 58g/mol

raport de masa ⇒ Mg:O:H = 24:32:2 = 12:16:1

29 p.m........12 p.m Mg....16 p.m O.....1 p.m H
100g...................x......................y.............z

x = 12×100/29 = 41,379 % Mg
y = 55,172 % O
z = 3,44% H


pag. 69. Chenar 1:

a) MCaCO₃ = ACa+AC+3AO = 40+12+3×16 = 100g/mol

%Ca = mCa/MCaCO₃×100 = 40/100×100 = 40
%C = 12/100×100 = 12
%O = 48/100×100 = 48

b) MCaO = ACa+AO = 40+16 = 56g/mol

%Ca = 40/56×100 = 71,42
%O = 28,571

c) MCH₄ = AC+4AH = 12+4×1 = 16g/mol

%C = 12/16×100 = 75
%H = 25

d) MMgCl₂ = AMg + 2ACl = 24+2×35,5 = 95g/mol

%Mg = 24/95×100 = 25,26
%Cl = 74,73

pag. 69. Chenar 2:

a) MH₂O = 18g/mol

18g H₂O....................16g O
36g H₂O......................xg O

x = 16×36/18 = 32g O

b) MH₂SO₄ = 98g/mol

1 mol H₂SO₄...........................4×16 = 64g O
2 moli H₂SO₄...............................x = 128g O

c) 1 kmol = 1000 moli
0,15 kmoli = 150 moli 

MSO₂ = 64g/mol

1 mol SO₂........................32g O
150 moli SO₂...................x = 4800g O = 4,8 kg O

pag. 69. Chenar 3:

a) MH₂O = 18g/mol

18g H₂O...................2g H
xg H₂O......................6g H

x = 18×6/2 = 54g H₂O

b) MPH₃ = AP+3AH = 31+3*1 = 34g/mol

34g PH₃.......................3g H
xg PH₃.........................6g H

x = 68g PH₃

c) MH₂CO₃ = 2AH + AC + 3AO = 2*1+12+3*16 = 62g/mol  

62g H₂CO₃....................2g H
xg H₂CO₃......................6g H

x = 186g H₂CO₃