Question

cum se deriveaza?$\frac{2x+1}{ \sqrt{ x^{2}+1 } }$

Answer 1

[tex] \frac{(2x+1)' \sqrt{x^2+1}- \sqrt{x^2+1} '(2x+1) }{x^2+1} = \frac{2 \sqrt{x^2+1}- \frac{x}{ \sqrt{x^2+1} }*(2x+1) }{x^2+1} = \frac{2(x^2+1-2x^2-x)}{(x^2+1) \sqrt{x^2+1} } = \\ \\ = \frac{2(-x^2-x+1)}{(x^2+1) \sqrt{x^2+1} } =- \frac{2(x^2+x-1)}{(x^2+1)\sqrt{x^2+1}} [/tex]