Question

Cum se fac astea? :))
Determinati valorile reale ale numarului m,stiind ca ecuatiile urmatoare sunt echivalente

3(2x+1)-10=2(x-3)+11 si 2mx+3(m-1)x+7=4(2m+1)-27

Answer 1

3(2x+1)-10=2(x+3)+11 => 6x+3-10=2x+6+11=>6x-2x=10-3+6+11=>4x=24=>x=6. A doua ecuatie:inlocuim x cu 6 : 2m+3m-3(x-7)=8m+4-27=>6m-3x+21=6m-23=>6m-3•6+21=8m-23=>6m-18+21=8m-23=>6m-8m=-23+18-21=>-2m=-5-21=>-2m=-26|•(-1)=>2m=26 => m=26:2=>m=13 ✔