Question

cum se face exercitiul acesta : [(c+41+56):2-20]:10=3

Answer 1

[(c+41+56):2-20]:10=3
(c+97):2-20 = 3 ×10
(c+97):2 = 30+20
(c+97):2 = 50
c+97 = 50×2
c+97 = 100
c = 100-97
c = 3
Verificare:
[(3+97):2 -20] :10 =[( 100:2)-20]:10 =
= (50-20):10 = 30:10 = 3

Answer 2

[(C+41+56):2-20]:10=3
[(C+97):2-20]:10=3
(C+97):2-20=3 x 10
(C+97):2-20=30
(C+97):2=30+20
(C+97):2=50
C+97=50 x 2
C+97=100
C=100-97
C=3
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